Why is the result of ('b'+'a'+ + 'a' + 'a').toLowerCase() 'banana'?JavaScript post request like a form...

A Word/Phrase for the Process of Classifying Something as a Sin

Is this curved text blend possible in Illustrator?

Solution to German Tank Problem

Why did Gandalf use a sword against the Balrog?

What does the phrase "pull off sick wheelies and flips" mean here?

Visa National - No Exit Stamp From France on Return to the UK

If clocks themselves are based on light signals, wouldn't we expect the measured speed of light to always be the same constant?

How to take the beginning and end parts of a list with simpler syntax?

Why is the result of ('b'+'a'+ + 'a' + 'a').toLowerCase() 'banana'?

The cat ate your input again!

What is a good class if we remove subclasses?

How can this older-style irrigation tee be replaced?

Simplification of numbers

Am I overreacting to my team leader's unethical requests?

Can anybody explain why using multicolumn changes the width of the four-column tabular environment?

How to remove threat that antivirus program indicates has to be manually deleted?

How to divide item stack in MC PE?

How to assign many blockers at the same time?

What is an internal dimension/glue/muglue?

Do beef farmed pastures net remove carbon emissions?

How does "Te vas a cansar" mean "You're going to get tired"?

Why did I get only 5 points even though I won?

How can I decide if my homebrew item should require attunement?

Heating Margarine in Pan = loss of calories?



Why is the result of ('b'+'a'+ + 'a' + 'a').toLowerCase() 'banana'?


JavaScript post request like a form submitHow do you access the matched groups in a JavaScript regular expression?Why is setTimeout(fn, 0) sometimes useful?What is the purpose of the var keyword and when should I use it (or omit it)?Get all unique values in a JavaScript array (remove duplicates)Storing Objects in HTML5 localStorageWhat is JSONP, and why was it created?Why does Google prepend while(1); to their JSON responses?How to decide when to use Node.js?Why does ++[[]][+[]]+[+[]] return the string “10”?






.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}







34















I was just practising JavaScript when one of my friends came across this JavaScript code.



('b'+'a'+ + 'a' + 'a').toLowerCase()


The above code answers "banana". Can anyone explain why?










share|improve this question









New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • 29





    because of + + 'a' === NaN

    – The Reason
    14 hours ago






  • 5





    That second plus is an unary operator: +"a" is NaN.

    – Gerardo Furtado
    14 hours ago








  • 17





    came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

    – Krishna Prashatt
    14 hours ago






  • 4





    And for those eager for more. See full fun list

    – Giddy Naya
    14 hours ago






  • 19





    for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

    – Jaromanda X
    13 hours ago


















34















I was just practising JavaScript when one of my friends came across this JavaScript code.



('b'+'a'+ + 'a' + 'a').toLowerCase()


The above code answers "banana". Can anyone explain why?










share|improve this question









New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

















  • 29





    because of + + 'a' === NaN

    – The Reason
    14 hours ago






  • 5





    That second plus is an unary operator: +"a" is NaN.

    – Gerardo Furtado
    14 hours ago








  • 17





    came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

    – Krishna Prashatt
    14 hours ago






  • 4





    And for those eager for more. See full fun list

    – Giddy Naya
    14 hours ago






  • 19





    for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

    – Jaromanda X
    13 hours ago














34












34








34


3






I was just practising JavaScript when one of my friends came across this JavaScript code.



('b'+'a'+ + 'a' + 'a').toLowerCase()


The above code answers "banana". Can anyone explain why?










share|improve this question









New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.











I was just practising JavaScript when one of my friends came across this JavaScript code.



('b'+'a'+ + 'a' + 'a').toLowerCase()


The above code answers "banana". Can anyone explain why?







javascript






share|improve this question









New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.










share|improve this question









New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








share|improve this question




share|improve this question








edited 2 hours ago









John Kugelman

259k58 gold badges420 silver badges470 bronze badges




259k58 gold badges420 silver badges470 bronze badges






New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.








asked 14 hours ago









Harshvardhan SharmaHarshvardhan Sharma

3013 silver badges9 bronze badges




3013 silver badges9 bronze badges




New contributor



Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




New contributor




Harshvardhan Sharma is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.













  • 29





    because of + + 'a' === NaN

    – The Reason
    14 hours ago






  • 5





    That second plus is an unary operator: +"a" is NaN.

    – Gerardo Furtado
    14 hours ago








  • 17





    came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

    – Krishna Prashatt
    14 hours ago






  • 4





    And for those eager for more. See full fun list

    – Giddy Naya
    14 hours ago






  • 19





    for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

    – Jaromanda X
    13 hours ago














  • 29





    because of + + 'a' === NaN

    – The Reason
    14 hours ago






  • 5





    That second plus is an unary operator: +"a" is NaN.

    – Gerardo Furtado
    14 hours ago








  • 17





    came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

    – Krishna Prashatt
    14 hours ago






  • 4





    And for those eager for more. See full fun list

    – Giddy Naya
    14 hours ago






  • 19





    for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

    – Jaromanda X
    13 hours ago








29




29





because of + + 'a' === NaN

– The Reason
14 hours ago





because of + + 'a' === NaN

– The Reason
14 hours ago




5




5





That second plus is an unary operator: +"a" is NaN.

– Gerardo Furtado
14 hours ago







That second plus is an unary operator: +"a" is NaN.

– Gerardo Furtado
14 hours ago






17




17





came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

– Krishna Prashatt
14 hours ago





came across this javascript code --> Where ever this code was came across surely ought to have the explanation.

– Krishna Prashatt
14 hours ago




4




4





And for those eager for more. See full fun list

– Giddy Naya
14 hours ago





And for those eager for more. See full fun list

– Giddy Naya
14 hours ago




19




19





for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

– Jaromanda X
13 hours ago





for future "learning" experience, why not do some investigating yourself. For example, remove the toLowerCase() ... replace the b, a, a, a with a, b, c, d ... which will surely make the result more apparent

– Jaromanda X
13 hours ago












1 Answer
1






active

oldest

votes


















49














+'a' resolves to NaN ("Not a Number") because it coerces a string to a number, while the character a cannot be parsed as a number.
Adding NaN to "ba" turns NaN into the string "NaN" due to type conversion, gives baNaN.
And then there is an a behind, giving baNaNa.



To lowercase it becomes banana.



The space between + + is to make the first one string concatenation and the second one a unary plus (i.e. "positive") operator.
You have the same result if you use 'ba'+(+'a')+'a', which is equivalent to 'ba'+'NaN'+'a'.






share|improve this answer























  • 7





    'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

    – t.niese
    14 hours ago













  • I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

    – Gerardo Furtado
    14 hours ago











  • @GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

    – SOFe
    14 hours ago








  • 2





    I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

    – SOFe
    14 hours ago






  • 4





    @SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

    – Gerardo Furtado
    14 hours ago














Your Answer






StackExchange.ifUsing("editor", function () {
StackExchange.using("externalEditor", function () {
StackExchange.using("snippets", function () {
StackExchange.snippets.init();
});
});
}, "code-snippets");

StackExchange.ready(function() {
var channelOptions = {
tags: "".split(" "),
id: "1"
};
initTagRenderer("".split(" "), "".split(" "), channelOptions);

StackExchange.using("externalEditor", function() {
// Have to fire editor after snippets, if snippets enabled
if (StackExchange.settings.snippets.snippetsEnabled) {
StackExchange.using("snippets", function() {
createEditor();
});
}
else {
createEditor();
}
});

function createEditor() {
StackExchange.prepareEditor({
heartbeatType: 'answer',
autoActivateHeartbeat: false,
convertImagesToLinks: true,
noModals: true,
showLowRepImageUploadWarning: true,
reputationToPostImages: 10,
bindNavPrevention: true,
postfix: "",
imageUploader: {
brandingHtml: "Powered by u003ca class="icon-imgur-white" href="https://imgur.com/"u003eu003c/au003e",
contentPolicyHtml: "User contributions licensed under u003ca href="https://creativecommons.org/licenses/by-sa/3.0/"u003ecc by-sa 3.0 with attribution requiredu003c/au003e u003ca href="https://stackoverflow.com/legal/content-policy"u003e(content policy)u003c/au003e",
allowUrls: true
},
onDemand: true,
discardSelector: ".discard-answer"
,immediatelyShowMarkdownHelp:true
});


}
});






Harshvardhan Sharma is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f57456188%2fwhy-is-the-result-of-ba-a-a-tolowercase-banana%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown

























1 Answer
1






active

oldest

votes








1 Answer
1






active

oldest

votes









active

oldest

votes






active

oldest

votes









49














+'a' resolves to NaN ("Not a Number") because it coerces a string to a number, while the character a cannot be parsed as a number.
Adding NaN to "ba" turns NaN into the string "NaN" due to type conversion, gives baNaN.
And then there is an a behind, giving baNaNa.



To lowercase it becomes banana.



The space between + + is to make the first one string concatenation and the second one a unary plus (i.e. "positive") operator.
You have the same result if you use 'ba'+(+'a')+'a', which is equivalent to 'ba'+'NaN'+'a'.






share|improve this answer























  • 7





    'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

    – t.niese
    14 hours ago













  • I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

    – Gerardo Furtado
    14 hours ago











  • @GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

    – SOFe
    14 hours ago








  • 2





    I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

    – SOFe
    14 hours ago






  • 4





    @SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

    – Gerardo Furtado
    14 hours ago


















49














+'a' resolves to NaN ("Not a Number") because it coerces a string to a number, while the character a cannot be parsed as a number.
Adding NaN to "ba" turns NaN into the string "NaN" due to type conversion, gives baNaN.
And then there is an a behind, giving baNaNa.



To lowercase it becomes banana.



The space between + + is to make the first one string concatenation and the second one a unary plus (i.e. "positive") operator.
You have the same result if you use 'ba'+(+'a')+'a', which is equivalent to 'ba'+'NaN'+'a'.






share|improve this answer























  • 7





    'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

    – t.niese
    14 hours ago













  • I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

    – Gerardo Furtado
    14 hours ago











  • @GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

    – SOFe
    14 hours ago








  • 2





    I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

    – SOFe
    14 hours ago






  • 4





    @SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

    – Gerardo Furtado
    14 hours ago
















49












49








49







+'a' resolves to NaN ("Not a Number") because it coerces a string to a number, while the character a cannot be parsed as a number.
Adding NaN to "ba" turns NaN into the string "NaN" due to type conversion, gives baNaN.
And then there is an a behind, giving baNaNa.



To lowercase it becomes banana.



The space between + + is to make the first one string concatenation and the second one a unary plus (i.e. "positive") operator.
You have the same result if you use 'ba'+(+'a')+'a', which is equivalent to 'ba'+'NaN'+'a'.






share|improve this answer















+'a' resolves to NaN ("Not a Number") because it coerces a string to a number, while the character a cannot be parsed as a number.
Adding NaN to "ba" turns NaN into the string "NaN" due to type conversion, gives baNaN.
And then there is an a behind, giving baNaNa.



To lowercase it becomes banana.



The space between + + is to make the first one string concatenation and the second one a unary plus (i.e. "positive") operator.
You have the same result if you use 'ba'+(+'a')+'a', which is equivalent to 'ba'+'NaN'+'a'.







share|improve this answer














share|improve this answer



share|improve this answer








edited 5 hours ago









Bergi

400k66 gold badges633 silver badges958 bronze badges




400k66 gold badges633 silver badges958 bronze badges










answered 14 hours ago









SOFeSOFe

3,1833 gold badges24 silver badges47 bronze badges




3,1833 gold badges24 silver badges47 bronze badges











  • 7





    'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

    – t.niese
    14 hours ago













  • I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

    – Gerardo Furtado
    14 hours ago











  • @GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

    – SOFe
    14 hours ago








  • 2





    I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

    – SOFe
    14 hours ago






  • 4





    @SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

    – Gerardo Furtado
    14 hours ago
















  • 7





    'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

    – t.niese
    14 hours ago













  • I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

    – Gerardo Furtado
    14 hours ago











  • @GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

    – SOFe
    14 hours ago








  • 2





    I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

    – SOFe
    14 hours ago






  • 4





    @SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

    – Gerardo Furtado
    14 hours ago










7




7





'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

– t.niese
14 hours ago







'ba'+(+'a')+'a' is equivalent to 'ba' + NaN + 'a'. The conversion to the string happens because 'ba' beeing a string as the time when 'ba' + NaN is performed. 1 + + 'a' + 1 is NaN because it is 1 + NaN + 1 and not 1 + 'NaN' + 1 which would result in 1NaN1

– t.niese
14 hours ago















I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

– Gerardo Furtado
14 hours ago





I believe there is some confusion between arithmetic operators and the unary plus in your answer. Technically speaking, the unary plus does not perform an arithmetic addition.

– Gerardo Furtado
14 hours ago













@GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

– SOFe
14 hours ago







@GerardoFurtado thanks. I made a typo when I wrote unary addition instead of unary plus. But it is a numeric-related operator nonetheless.

– SOFe
14 hours ago






2




2





I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

– SOFe
14 hours ago





I guess that's not really important. I just checked the ES3 spec and realized the term "arithmetic operator" never appeared in the spec, so it's just how we define our own words. But indeed, you're right to say that "unary plus just converts the operand to Number type" (which is a pointless operator anyway).

– SOFe
14 hours ago




4




4





@SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

– Gerardo Furtado
14 hours ago







@SOFe In my opinion the distinction is important. For better explaining, you have two different operators that use the same symbol (+). I'm using the ECMA specifications here: One is the addition operator (ecma-international.org/ecma-262/10.0/…). The other one is the unary operator (ecma-international.org/ecma-262/10.0/#sec-unary-plus-operator). They are different. To summarise, it doesn't "attempts to perform an arithmetic operation on a string", as you mentioned in your answer.

– Gerardo Furtado
14 hours ago










Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.







Got a question that you can’t ask on public Stack Overflow? Learn more about sharing private information with Stack Overflow for Teams.












Harshvardhan Sharma is a new contributor. Be nice, and check out our Code of Conduct.










draft saved

draft discarded


















Harshvardhan Sharma is a new contributor. Be nice, and check out our Code of Conduct.













Harshvardhan Sharma is a new contributor. Be nice, and check out our Code of Conduct.












Harshvardhan Sharma is a new contributor. Be nice, and check out our Code of Conduct.
















Thanks for contributing an answer to Stack Overflow!


  • Please be sure to answer the question. Provide details and share your research!

But avoid



  • Asking for help, clarification, or responding to other answers.

  • Making statements based on opinion; back them up with references or personal experience.


To learn more, see our tips on writing great answers.




draft saved


draft discarded














StackExchange.ready(
function () {
StackExchange.openid.initPostLogin('.new-post-login', 'https%3a%2f%2fstackoverflow.com%2fquestions%2f57456188%2fwhy-is-the-result-of-ba-a-a-tolowercase-banana%23new-answer', 'question_page');
}
);

Post as a guest















Required, but never shown





















































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown

































Required, but never shown














Required, but never shown












Required, but never shown







Required, but never shown







Popular posts from this blog

Taj Mahal Inhaltsverzeichnis Aufbau | Geschichte | 350-Jahr-Feier | Heutige Bedeutung | Siehe auch |...

Baia Sprie Cuprins Etimologie | Istorie | Demografie | Politică și administrație | Arii naturale...

Nicolae Petrescu-Găină Cuprins Biografie | Opera | In memoriam | Varia | Controverse, incertitudini...