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}

1

I want to do this: readarray var1 < <(find "/path/to/dir" ( $var2 ) | sort)

echo $var2

user@domain:~# -name "*.avi" -o -name "*.mkv"

Unfortunately, my script does not work. Please, tell me where I do a mistake.

bash shell

share|improve this question

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'd be interested in why you need the sorting of the results. You cold get this in the zsh shell in a much more convenient and safe way which would not rely on the pathnames being sane (containing no newlines).
  
  – Kusalananda♦
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Just I'm newer in Linux (more precisely in Ubuntu). if you are telling me that your case is better I will be glad to see it.
  
  – UnixUser
  2 hours ago
  

  
  
  
  

add a comment | 

1

I want to do this: readarray var1 < <(find "/path/to/dir" ( $var2 ) | sort)

echo $var2

user@domain:~# -name "*.avi" -o -name "*.mkv"

Unfortunately, my script does not work. Please, tell me where I do a mistake.

bash shell

share|improve this question

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'd be interested in why you need the sorting of the results. You cold get this in the zsh shell in a much more convenient and safe way which would not rely on the pathnames being sane (containing no newlines).
  
  – Kusalananda♦
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Just I'm newer in Linux (more precisely in Ubuntu). if you are telling me that your case is better I will be glad to see it.
  
  – UnixUser
  2 hours ago
  

  
  
  
  

add a comment | 

I want to do this: readarray var1 < <(find "/path/to/dir" ( $var2 ) | sort)

echo $var2

user@domain:~# -name "*.avi" -o -name "*.mkv"

Unfortunately, my script does not work. Please, tell me where I do a mistake.

bash shell

share|improve this question

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

echo $var2

user@domain:~# -name "*.avi" -o -name "*.mkv"

share|improve this question

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

share|improve this question

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

edited 46 mins ago

steeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

asked 3 hours ago

UnixUserUnixUser

2744 bronze badges

1 Answer
1

active

oldest

votes

2

Use an array:

var2=( -name "*.avi" -o -name "*.mkv" )



readarray var1 < <(find "/path/to/dir" ( "${var2[@]}" ) | sort)

See the somewhat related How can we run a command stored in a variable?

share|improve this answer

edited 2 hours ago

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I do it without array? Only variable. Is it possibly?
  
  – UnixUser
  2 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @UnixUser You'd better let us know why you wouldn't want to use an array. Using an array is the correct way of handling this.
  
  – Kusalananda♦
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ... you're already using an array for var1, so it's not like you could port this code to a shell that doesn't support arrays
  
  – steeldriver
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks. You help me.
  
  – UnixUser
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda I want to understand what options I have. Thanks too.
  
  – UnixUser
  2 hours ago
  

  
  
  
  

add a comment | 

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2

Use an array:

var2=( -name "*.avi" -o -name "*.mkv" )



readarray var1 < <(find "/path/to/dir" ( "${var2[@]}" ) | sort)

See the somewhat related How can we run a command stored in a variable?

share|improve this answer

edited 2 hours ago

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I do it without array? Only variable. Is it possibly?
  
  – UnixUser
  2 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @UnixUser You'd better let us know why you wouldn't want to use an array. Using an array is the correct way of handling this.
  
  – Kusalananda♦
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ... you're already using an array for var1, so it's not like you could port this code to a shell that doesn't support arrays
  
  – steeldriver
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks. You help me.
  
  – UnixUser
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda I want to understand what options I have. Thanks too.
  
  – UnixUser
  2 hours ago
  

  
  
  
  

add a comment | 

2

Use an array:

var2=( -name "*.avi" -o -name "*.mkv" )



readarray var1 < <(find "/path/to/dir" ( "${var2[@]}" ) | sort)

See the somewhat related How can we run a command stored in a variable?

share|improve this answer

edited 2 hours ago

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Can I do it without array? Only variable. Is it possibly?
  
  – UnixUser
  2 hours ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @UnixUser You'd better let us know why you wouldn't want to use an array. Using an array is the correct way of handling this.
  
  – Kusalananda♦
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  ... you're already using an array for var1, so it's not like you could port this code to a shell that doesn't support arrays
  
  – steeldriver
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Thanks. You help me.
  
  – UnixUser
  2 hours ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda I want to understand what options I have. Thanks too.
  
  – UnixUser
  2 hours ago
  

  
  
  
  

add a comment | 

Use an array:

var2=( -name "*.avi" -o -name "*.mkv" )



readarray var1 < <(find "/path/to/dir" ( "${var2[@]}" ) | sort)

See the somewhat related How can we run a command stored in a variable?

share|improve this answer

edited 2 hours ago

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

var2=( -name "*.avi" -o -name "*.mkv" )



readarray var1 < <(find "/path/to/dir" ( "${var2[@]}" ) | sort)

share|improve this answer

edited 2 hours ago

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges

answered 3 hours ago

steeldriversteeldriver

40.8k44 gold badges5656 silver badges9393 bronze badges