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0

Why do this script work?

str=( -name "*.conf" -o -name "test test" )

find ./ ( "${str[@]}" )

And this script not work?

str[0]="-name"

str[1]=""*.conf""

str[2]="-o"

str[3]="-name"

str[4]=""test test""

find ./ ( "${str[@]}" )

It looks like error here: str[1]=""*.conf""

I'm interested in the second case.

shell

share|improve this question

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  To see how they differ, turn debugging on in your shell (set -x)
  
  – steeldriver
  14 mins ago
  

  
  
  
  

add a comment | 

0

Why do this script work?

str=( -name "*.conf" -o -name "test test" )

find ./ ( "${str[@]}" )

And this script not work?

str[0]="-name"

str[1]=""*.conf""

str[2]="-o"

str[3]="-name"

str[4]=""test test""

find ./ ( "${str[@]}" )

It looks like error here: str[1]=""*.conf""

I'm interested in the second case.

shell

share|improve this question

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  To see how they differ, turn debugging on in your shell (set -x)
  
  – steeldriver
  14 mins ago
  

  
  
  
  

add a comment | 

Why do this script work?

str=( -name "*.conf" -o -name "test test" )

find ./ ( "${str[@]}" )

And this script not work?

str[0]="-name"

str[1]=""*.conf""

str[2]="-o"

str[3]="-name"

str[4]=""test test""

find ./ ( "${str[@]}" )

It looks like error here: str[1]=""*.conf""

I'm interested in the second case.

shell

share|improve this question

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

str=( -name "*.conf" -o -name "test test" )

find ./ ( "${str[@]}" )

str[0]="-name"

str[1]=""*.conf""

str[2]="-o"

str[3]="-name"

str[4]=""test test""

find ./ ( "${str[@]}" )

share|improve this question

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

share|improve this question

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

asked 37 mins ago

UnixUserUnixUser

2544 bronze badges

1 Answer
1

active

oldest

votes

0

This:

str=( -name "*.conf" -o -name "test test" )

Is (usually) the same as this:

str=( "-name" "*.conf" "-o" "-name" "test test" )

Most of those quotes are omitted because they're not necessary - there are no wildcards for filename expansion, or whitespace characters from the default IFS that might cause field splitting for those elements.

So the equivalent could be:

declare -a str

str[0]="-name"

str[1]="*.conf"

str[2]="-o"

str[3]="-name"

str[4]="test test"

Or:

declare -a str

str[0]=-name

str[1]=*.conf    # no filename expansion in variable assignment

str[2]=-o

str[3]=-name

str[4]="test test"

share|improve this answer

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

add a comment | 

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0

This:

str=( -name "*.conf" -o -name "test test" )

Is (usually) the same as this:

str=( "-name" "*.conf" "-o" "-name" "test test" )

Most of those quotes are omitted because they're not necessary - there are no wildcards for filename expansion, or whitespace characters from the default IFS that might cause field splitting for those elements.

So the equivalent could be:

declare -a str

str[0]="-name"

str[1]="*.conf"

str[2]="-o"

str[3]="-name"

str[4]="test test"

Or:

declare -a str

str[0]=-name

str[1]=*.conf    # no filename expansion in variable assignment

str[2]=-o

str[3]=-name

str[4]="test test"

share|improve this answer

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

add a comment | 

0

This:

str=( -name "*.conf" -o -name "test test" )

Is (usually) the same as this:

str=( "-name" "*.conf" "-o" "-name" "test test" )

Most of those quotes are omitted because they're not necessary - there are no wildcards for filename expansion, or whitespace characters from the default IFS that might cause field splitting for those elements.

So the equivalent could be:

declare -a str

str[0]="-name"

str[1]="*.conf"

str[2]="-o"

str[3]="-name"

str[4]="test test"

Or:

declare -a str

str[0]=-name

str[1]=*.conf    # no filename expansion in variable assignment

str[2]=-o

str[3]=-name

str[4]="test test"

share|improve this answer

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

add a comment | 

This:

str=( -name "*.conf" -o -name "test test" )

Is (usually) the same as this:

str=( "-name" "*.conf" "-o" "-name" "test test" )

Most of those quotes are omitted because they're not necessary - there are no wildcards for filename expansion, or whitespace characters from the default IFS that might cause field splitting for those elements.

So the equivalent could be:

declare -a str

str[0]="-name"

str[1]="*.conf"

str[2]="-o"

str[3]="-name"

str[4]="test test"

Or:

declare -a str

str[0]=-name

str[1]=*.conf    # no filename expansion in variable assignment

str[2]=-o

str[3]=-name

str[4]="test test"

share|improve this answer

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

str=( -name "*.conf" -o -name "test test" )

str=( "-name" "*.conf" "-o" "-name" "test test" )

declare -a str

str[0]="-name"

str[1]="*.conf"

str[2]="-o"

str[3]="-name"

str[4]="test test"

declare -a str

str[0]=-name

str[1]=*.conf    # no filename expansion in variable assignment

str[2]=-o

str[3]=-name

str[4]="test test"

share|improve this answer

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges

answered 20 mins ago

murumuru

41.6k55 gold badges101101 silver badges175175 bronze badges