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How to plot multiple functions from a list
How can I create a table of sliders?PlotLegends from a ListUsing Multiple Kernels When Making PlotsPlot the minimum of a list of functionsHow do I set a PlotStyle when plotting a Table of functions?Evaluating and Plotting Multiple Zero-Counting FunctionsHow to make a table with a jump in range?How to automate plotting of many functions?Plot for a list of parametersBreaking up a list of lists
.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
}
$begingroup$
I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?
Table[ContourPlot3D[f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
plotting table
$endgroup$
add a comment |
$begingroup$
I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?
Table[ContourPlot3D[f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
plotting table
$endgroup$
add a comment |
$begingroup$
I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?
Table[ContourPlot3D[f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
plotting table
$endgroup$
I'd like to get separate plots for the functions in a list, and I'm trying the following, which doesn't work. What is the correct way to do that?
Table[ContourPlot3D[f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
plotting table
plotting table
asked 8 hours ago
FrankFrank
2371 silver badge7 bronze badges
2371 silver badge7 bronze badges
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add a comment |
3 Answers
3
active
oldest
votes
$begingroup$
Table[ContourPlot3D[
Evaluate[f], {x, -2, 2}, {y, -2, 2}, {z, -2,
2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0,
x + y^2 + z + x y^2 z == 0}}]
Just add Evaluate
$endgroup$
add a comment |
$begingroup$
Instead of Table
you could use Map
ContourPlot3D[#, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] & /@ {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}
$endgroup$
add a comment |
$begingroup$
Using Table
Table[ContourPlot3D[
Evaluate@f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0,
x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
$endgroup$
add a comment |
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3 Answers
3
active
oldest
votes
3 Answers
3
active
oldest
votes
active
oldest
votes
active
oldest
votes
$begingroup$
Table[ContourPlot3D[
Evaluate[f], {x, -2, 2}, {y, -2, 2}, {z, -2,
2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0,
x + y^2 + z + x y^2 z == 0}}]
Just add Evaluate
$endgroup$
add a comment |
$begingroup$
Table[ContourPlot3D[
Evaluate[f], {x, -2, 2}, {y, -2, 2}, {z, -2,
2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0,
x + y^2 + z + x y^2 z == 0}}]
Just add Evaluate
$endgroup$
add a comment |
$begingroup$
Table[ContourPlot3D[
Evaluate[f], {x, -2, 2}, {y, -2, 2}, {z, -2,
2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0,
x + y^2 + z + x y^2 z == 0}}]
Just add Evaluate
$endgroup$
Table[ContourPlot3D[
Evaluate[f], {x, -2, 2}, {y, -2, 2}, {z, -2,
2}], {f, {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0,
x + y^2 + z + x y^2 z == 0}}]
Just add Evaluate
answered 8 hours ago
yarchikyarchik
4,42610 silver badges34 bronze badges
4,42610 silver badges34 bronze badges
add a comment |
add a comment |
$begingroup$
Instead of Table
you could use Map
ContourPlot3D[#, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] & /@ {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}
$endgroup$
add a comment |
$begingroup$
Instead of Table
you could use Map
ContourPlot3D[#, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] & /@ {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}
$endgroup$
add a comment |
$begingroup$
Instead of Table
you could use Map
ContourPlot3D[#, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] & /@ {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}
$endgroup$
Instead of Table
you could use Map
ContourPlot3D[#, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}] & /@ {x + y + z + x y z == 0, x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}
answered 8 hours ago
That Gravity GuyThat Gravity Guy
2,2761 gold badge6 silver badges15 bronze badges
2,2761 gold badge6 silver badges15 bronze badges
add a comment |
add a comment |
$begingroup$
Using Table
Table[ContourPlot3D[
Evaluate@f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0,
x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
$endgroup$
add a comment |
$begingroup$
Using Table
Table[ContourPlot3D[
Evaluate@f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0,
x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
$endgroup$
add a comment |
$begingroup$
Using Table
Table[ContourPlot3D[
Evaluate@f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0,
x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
$endgroup$
Using Table
Table[ContourPlot3D[
Evaluate@f, {x, -2, 2}, {y, -2, 2}, {z, -2, 2}], {f, {x + y + z + x y z == 0,
x + y + z^2 + x y z^2 == 0, x + y^2 + z + x y^2 z == 0}}]
answered 8 hours ago
Rohit NamjoshiRohit Namjoshi
2,0571 gold badge4 silver badges16 bronze badges
2,0571 gold badge4 silver badges16 bronze badges
add a comment |
add a comment |
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