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Compare if the newest file in the directory is different from the previous one

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.everyoneloves__top-leaderboard:empty,.everyoneloves__mid-leaderboard:empty,.everyoneloves__bot-mid-leaderboard:empty{ margin-bottom:0;
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0

1

I have the following script:

#!/bin/bash

y=$(ls -t ./pics/0/*.png | head -n 2 | tail -n 1)

new=$(ls -t ./pics/0/*.png | head -n 1)

while true

do

 if cmp --silent "$y" "$new" ; then

y=$(ls -t ./pics/0/*.png | head -n 1)

    base64 $y | tr -d 'n' | sed '$ a '

new=$(ls -t ./pics/0/*.png | head -n 1)

 fi

done

What am I doing wrong?
To be clear my goal is to compare whether the newest file is different from the previous newest file and only if it is generate a unique BASE64 to STDOUT (meaning it should be printed only ONCE).

bash

share|improve this question

edited yesterday

Sir Muffington

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are missing spaces in your if. It is if [ cmp --silent $y $new != null ].
  
  – guillermo chamorro
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @guillermochamorro Now it says that I've got too many arguments..
  
  – Sir Muffington
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @steeldriver this code works, but the script prints out multiple duplicate base64 strings, I probably made a logical error in doing the script then? any clue how to fix it so that prints unique base64 every time a file is changed?
  
  – Sir Muffington
  2 days ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Removing the --silent flag seems to reduce the number of occurrences of base64 strings to only 3-4 per second, when a new file is added every second. Is this a bug???
  
  – Sir Muffington
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please take a look: shellcheck.net
  
  – Cyrus
  2 days ago
  

  
  
  
  

 | 
show 10 more comments

0

1

I have the following script:

#!/bin/bash

y=$(ls -t ./pics/0/*.png | head -n 2 | tail -n 1)

new=$(ls -t ./pics/0/*.png | head -n 1)

while true

do

 if cmp --silent "$y" "$new" ; then

y=$(ls -t ./pics/0/*.png | head -n 1)

    base64 $y | tr -d 'n' | sed '$ a '

new=$(ls -t ./pics/0/*.png | head -n 1)

 fi

done

What am I doing wrong?
To be clear my goal is to compare whether the newest file is different from the previous newest file and only if it is generate a unique BASE64 to STDOUT (meaning it should be printed only ONCE).

bash

share|improve this question

edited yesterday

Sir Muffington

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  You are missing spaces in your if. It is if [ cmp --silent $y $new != null ].
  
  – guillermo chamorro
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @guillermochamorro Now it says that I've got too many arguments..
  
  – Sir Muffington
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @steeldriver this code works, but the script prints out multiple duplicate base64 strings, I probably made a logical error in doing the script then? any clue how to fix it so that prints unique base64 every time a file is changed?
  
  – Sir Muffington
  2 days ago
  
  
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Removing the --silent flag seems to reduce the number of occurrences of base64 strings to only 3-4 per second, when a new file is added every second. Is this a bug???
  
  – Sir Muffington
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  1
  

  
  
  
  
  
  

  
  
  Please take a look: shellcheck.net
  
  – Cyrus
  2 days ago
  

  
  
  
  

 | 
show 10 more comments

I have the following script:

#!/bin/bash

y=$(ls -t ./pics/0/*.png | head -n 2 | tail -n 1)

new=$(ls -t ./pics/0/*.png | head -n 1)

while true

do

 if cmp --silent "$y" "$new" ; then

y=$(ls -t ./pics/0/*.png | head -n 1)

    base64 $y | tr -d 'n' | sed '$ a '

new=$(ls -t ./pics/0/*.png | head -n 1)

 fi

done

What am I doing wrong?
To be clear my goal is to compare whether the newest file is different from the previous newest file and only if it is generate a unique BASE64 to STDOUT (meaning it should be printed only ONCE).

bash

share|improve this question

edited yesterday

Sir Muffington

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

#!/bin/bash

y=$(ls -t ./pics/0/*.png | head -n 2 | tail -n 1)

new=$(ls -t ./pics/0/*.png | head -n 1)

while true

do

 if cmp --silent "$y" "$new" ; then

y=$(ls -t ./pics/0/*.png | head -n 1)

    base64 $y | tr -d 'n' | sed '$ a '

new=$(ls -t ./pics/0/*.png | head -n 1)

 fi

done

share|improve this question

edited yesterday

Sir Muffington

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

share|improve this question

edited yesterday

Sir Muffington

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

New contributor

Sir Muffington is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

asked 2 days ago

Sir MuffingtonSir Muffington

122 bronze badges

1 Answer
1

active

oldest

votes

0

Please note that the following snippet will NOT work with filenames containing spaces, tabs or newlines.

To find out more about the find-command used here, please reference https://unix.stackexchange.com/a/240424/364705

#!/bin/bash

lastrun=''

while true; do

  read -r newer older <<< 

    $(find . -type f -exec stat -c '%Y %n' {} ; 

    | sort -nr 

    | awk 'NR==1,NR==2 {print $2}'

    | xargs )



  if [ "$newer" == "$lastrun" ]; then

    :

  else

    if ! cmp "$newer" "$older" > /dev/null ; then

      base64 "$newer"| tr -d 'n' | sed '$ a '

      lastrun="$newer"

    fi

  fi

done

And a solution using inotify-wait:

#!/bin/bash

lastfile=''

inotifywait -m /path/to/somewhere -e close -e moved_to |

while read path action file; do

  if [ "$lastfile" != '' ];then

    if ! cmp "${path}$file" "${path}${lastfile}" > /dev/null  ; then

    base64 "${path}${file}"

    fi

  fi

    lastfile="$file"

done

share|improve this answer

edited yesterday

answered yesterday

markgrafmarkgraf

34277 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This works. However, when the file amount in the folder goes around over 1000 it appears to skip 1-3 files per second. Is this a performance limitation of find?
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could be a shell-script isn't fast enough if the files are coming quickly. If you do not have any subdirectories in the directory where you are running this, then you can drop the find..-exec and just do stat -c '%Y %n' * instead. That should be faster.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If that still isn't fast enough, maybe look into inotifywait to trigger an action whenever a file is created/moved_to your directory.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It doesn't appear to be working without the find part. I already wrote a prototype for inotifywait, but still need to format it properly.
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $(stat -c '%Y %n' * | sort -nr ... instead of $(find . -type f -exec stat -c '%Y %n' {} ; | sort -nr .... But only if there are no subdirs.
  
  – markgraf
  yesterday
  
  
  

  
  
  
  

 | 
show 3 more comments

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0

Please note that the following snippet will NOT work with filenames containing spaces, tabs or newlines.

To find out more about the find-command used here, please reference https://unix.stackexchange.com/a/240424/364705

#!/bin/bash

lastrun=''

while true; do

  read -r newer older <<< 

    $(find . -type f -exec stat -c '%Y %n' {} ; 

    | sort -nr 

    | awk 'NR==1,NR==2 {print $2}'

    | xargs )



  if [ "$newer" == "$lastrun" ]; then

    :

  else

    if ! cmp "$newer" "$older" > /dev/null ; then

      base64 "$newer"| tr -d 'n' | sed '$ a '

      lastrun="$newer"

    fi

  fi

done

And a solution using inotify-wait:

#!/bin/bash

lastfile=''

inotifywait -m /path/to/somewhere -e close -e moved_to |

while read path action file; do

  if [ "$lastfile" != '' ];then

    if ! cmp "${path}$file" "${path}${lastfile}" > /dev/null  ; then

    base64 "${path}${file}"

    fi

  fi

    lastfile="$file"

done

share|improve this answer

edited yesterday

answered yesterday

markgrafmarkgraf

34277 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This works. However, when the file amount in the folder goes around over 1000 it appears to skip 1-3 files per second. Is this a performance limitation of find?
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could be a shell-script isn't fast enough if the files are coming quickly. If you do not have any subdirectories in the directory where you are running this, then you can drop the find..-exec and just do stat -c '%Y %n' * instead. That should be faster.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If that still isn't fast enough, maybe look into inotifywait to trigger an action whenever a file is created/moved_to your directory.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It doesn't appear to be working without the find part. I already wrote a prototype for inotifywait, but still need to format it properly.
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $(stat -c '%Y %n' * | sort -nr ... instead of $(find . -type f -exec stat -c '%Y %n' {} ; | sort -nr .... But only if there are no subdirs.
  
  – markgraf
  yesterday
  
  
  

  
  
  
  

 | 
show 3 more comments

0

Please note that the following snippet will NOT work with filenames containing spaces, tabs or newlines.

To find out more about the find-command used here, please reference https://unix.stackexchange.com/a/240424/364705

#!/bin/bash

lastrun=''

while true; do

  read -r newer older <<< 

    $(find . -type f -exec stat -c '%Y %n' {} ; 

    | sort -nr 

    | awk 'NR==1,NR==2 {print $2}'

    | xargs )



  if [ "$newer" == "$lastrun" ]; then

    :

  else

    if ! cmp "$newer" "$older" > /dev/null ; then

      base64 "$newer"| tr -d 'n' | sed '$ a '

      lastrun="$newer"

    fi

  fi

done

And a solution using inotify-wait:

#!/bin/bash

lastfile=''

inotifywait -m /path/to/somewhere -e close -e moved_to |

while read path action file; do

  if [ "$lastfile" != '' ];then

    if ! cmp "${path}$file" "${path}${lastfile}" > /dev/null  ; then

    base64 "${path}${file}"

    fi

  fi

    lastfile="$file"

done

share|improve this answer

edited yesterday

answered yesterday

markgrafmarkgraf

34277 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  This works. However, when the file amount in the folder goes around over 1000 it appears to skip 1-3 files per second. Is this a performance limitation of find?
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Could be a shell-script isn't fast enough if the files are coming quickly. If you do not have any subdirectories in the directory where you are running this, then you can drop the find..-exec and just do stat -c '%Y %n' * instead. That should be faster.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  If that still isn't fast enough, maybe look into inotifywait to trigger an action whenever a file is created/moved_to your directory.
  
  – markgraf
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  It doesn't appear to be working without the find part. I already wrote a prototype for inotifywait, but still need to format it properly.
  
  – Sir Muffington
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  $(stat -c '%Y %n' * | sort -nr ... instead of $(find . -type f -exec stat -c '%Y %n' {} ; | sort -nr .... But only if there are no subdirs.
  
  – markgraf
  yesterday
  
  
  

  
  
  
  

 | 
show 3 more comments

Please note that the following snippet will NOT work with filenames containing spaces, tabs or newlines.

To find out more about the find-command used here, please reference https://unix.stackexchange.com/a/240424/364705

#!/bin/bash

lastrun=''

while true; do

  read -r newer older <<< 

    $(find . -type f -exec stat -c '%Y %n' {} ; 

    | sort -nr 

    | awk 'NR==1,NR==2 {print $2}'

    | xargs )



  if [ "$newer" == "$lastrun" ]; then

    :

  else

    if ! cmp "$newer" "$older" > /dev/null ; then

      base64 "$newer"| tr -d 'n' | sed '$ a '

      lastrun="$newer"

    fi

  fi

done

And a solution using inotify-wait:

#!/bin/bash

lastfile=''

inotifywait -m /path/to/somewhere -e close -e moved_to |

while read path action file; do

  if [ "$lastfile" != '' ];then

    if ! cmp "${path}$file" "${path}${lastfile}" > /dev/null  ; then

    base64 "${path}${file}"

    fi

  fi

    lastfile="$file"

done

share|improve this answer

edited yesterday

answered yesterday

markgrafmarkgraf

34277 bronze badges

#!/bin/bash

lastrun=''

while true; do

  read -r newer older <<< 

    $(find . -type f -exec stat -c '%Y %n' {} ; 

    | sort -nr 

    | awk 'NR==1,NR==2 {print $2}'

    | xargs )



  if [ "$newer" == "$lastrun" ]; then

    :

  else

    if ! cmp "$newer" "$older" > /dev/null ; then

      base64 "$newer"| tr -d 'n' | sed '$ a '

      lastrun="$newer"

    fi

  fi

done

#!/bin/bash

lastfile=''

inotifywait -m /path/to/somewhere -e close -e moved_to |

while read path action file; do

  if [ "$lastfile" != '' ];then

    if ! cmp "${path}$file" "${path}${lastfile}" > /dev/null  ; then

    base64 "${path}${file}"

    fi

  fi

    lastfile="$file"

done

share|improve this answer

edited yesterday

answered yesterday

markgrafmarkgraf

34277 bronze badges

answered yesterday

markgrafmarkgraf

34277 bronze badges

answered yesterday

markgrafmarkgraf

34277 bronze badges