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Create and use Object Variable

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Create and use Object Variable


pass actionFunction name of variable to set in controller?Record Create on the GoogleDoc object within Visual WorkflowDate arithmetic expressions must use Integer or Long argumentsFill the WhoId and WhatId fields when create an eventLightning, display object fields on a different tabWhat fields and syntax for constructor to create records to add to a list<object>Create related object of certain Record Type on ObjectUsing Flow Designer, I'm trying to iterate through a list of items and put the value of a field in a list separated by a semi-colonHow to use an apex class variable in LWC javascript?Clarification on variable scope rules in Apex






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3















How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":



        for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
if(info.isAvailable()) {
//Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
//in Object Name and Id fields.

//myObject.Name = info.getName();
//myObject.Name = info.getRecordTypeId();
}
}


I imagined an object variable like:



Object myObject = {Name, Id}


But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?










share|improve this question







New contributor



Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.




























    3















    How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":



            for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
    if(info.isAvailable()) {
    //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
    //in Object Name and Id fields.

    //myObject.Name = info.getName();
    //myObject.Name = info.getRecordTypeId();
    }
    }


    I imagined an object variable like:



    Object myObject = {Name, Id}


    But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?










    share|improve this question







    New contributor



    Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
    Check out our Code of Conduct.
























      3












      3








      3








      How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":



              for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
      if(info.isAvailable()) {
      //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
      //in Object Name and Id fields.

      //myObject.Name = info.getName();
      //myObject.Name = info.getRecordTypeId();
      }
      }


      I imagined an object variable like:



      Object myObject = {Name, Id}


      But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?










      share|improve this question







      New contributor



      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.











      How do I create an "Object" variable with two fields inside and assign value to these fields through this "for":



              for(RecordTypeInfo info: Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
      if(info.isAvailable()) {
      //Here i would add the value of the variables "info.getRecordTypeId(), info.getName()"
      //in Object Name and Id fields.

      //myObject.Name = info.getName();
      //myObject.Name = info.getRecordTypeId();
      }
      }


      I imagined an object variable like:



      Object myObject = {Name, Id}


      But I don't think that's how you create it. And if it is not ideal to use variable "Object" what would it be?







      apex lightning






      share|improve this question







      New contributor



      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.










      share|improve this question







      New contributor



      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      share|improve this question




      share|improve this question






      New contributor



      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.








      asked 9 hours ago









      Diego Edargo PessoaDiego Edargo Pessoa

      182 bronze badges




      182 bronze badges




      New contributor



      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.




      New contributor




      Diego Edargo Pessoa is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
      Check out our Code of Conduct.



























          2 Answers
          2






          active

          oldest

          votes


















          3














          You can use List<Object> and List<List<Object>> to store different object like an array. Here is example



          string name='Dhanik';
          string id='111';
          List<Object> myObject = new List<Object>{name,id};
          List<List<Object>> objects=new List<List<Object>>();
          objects.add(myObject);
          integer num1=1;
          myObject = new List<Object>{name,num1};
          objects.add(myObject);
          system.debug('myObject:' + objects);
          system.debug('myObject:' + objects[0]);





          share|improve this answer


























          • Thanks! @Dhanik Lal Sahni

            – Diego Edargo Pessoa
            8 hours ago



















          2














          It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.



          public class RecordTypeInfoObj {
          @AuraEnabled
          public Id recordTypeId {get;set;}
          @AuraEnabled
          public String name {get;set;}

          public RecordTypeInfoObj(Id recordTypeId, String name) {
          this.recordTypeId = recordTypeId;
          this.name = name;
          }
          }


          List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
          for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
          if(info.isAvailable()) {
          recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
          }
          }


          In lightning component define the following attribute



          <aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />





          share|improve this answer




























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            2 Answers
            2






            active

            oldest

            votes








            2 Answers
            2






            active

            oldest

            votes









            active

            oldest

            votes






            active

            oldest

            votes









            3














            You can use List<Object> and List<List<Object>> to store different object like an array. Here is example



            string name='Dhanik';
            string id='111';
            List<Object> myObject = new List<Object>{name,id};
            List<List<Object>> objects=new List<List<Object>>();
            objects.add(myObject);
            integer num1=1;
            myObject = new List<Object>{name,num1};
            objects.add(myObject);
            system.debug('myObject:' + objects);
            system.debug('myObject:' + objects[0]);





            share|improve this answer


























            • Thanks! @Dhanik Lal Sahni

              – Diego Edargo Pessoa
              8 hours ago
















            3














            You can use List<Object> and List<List<Object>> to store different object like an array. Here is example



            string name='Dhanik';
            string id='111';
            List<Object> myObject = new List<Object>{name,id};
            List<List<Object>> objects=new List<List<Object>>();
            objects.add(myObject);
            integer num1=1;
            myObject = new List<Object>{name,num1};
            objects.add(myObject);
            system.debug('myObject:' + objects);
            system.debug('myObject:' + objects[0]);





            share|improve this answer


























            • Thanks! @Dhanik Lal Sahni

              – Diego Edargo Pessoa
              8 hours ago














            3












            3








            3







            You can use List<Object> and List<List<Object>> to store different object like an array. Here is example



            string name='Dhanik';
            string id='111';
            List<Object> myObject = new List<Object>{name,id};
            List<List<Object>> objects=new List<List<Object>>();
            objects.add(myObject);
            integer num1=1;
            myObject = new List<Object>{name,num1};
            objects.add(myObject);
            system.debug('myObject:' + objects);
            system.debug('myObject:' + objects[0]);





            share|improve this answer













            You can use List<Object> and List<List<Object>> to store different object like an array. Here is example



            string name='Dhanik';
            string id='111';
            List<Object> myObject = new List<Object>{name,id};
            List<List<Object>> objects=new List<List<Object>>();
            objects.add(myObject);
            integer num1=1;
            myObject = new List<Object>{name,num1};
            objects.add(myObject);
            system.debug('myObject:' + objects);
            system.debug('myObject:' + objects[0]);






            share|improve this answer












            share|improve this answer



            share|improve this answer










            answered 9 hours ago









            Dhanik Lal SahniDhanik Lal Sahni

            9573 silver badges11 bronze badges




            9573 silver badges11 bronze badges
















            • Thanks! @Dhanik Lal Sahni

              – Diego Edargo Pessoa
              8 hours ago



















            • Thanks! @Dhanik Lal Sahni

              – Diego Edargo Pessoa
              8 hours ago

















            Thanks! @Dhanik Lal Sahni

            – Diego Edargo Pessoa
            8 hours ago





            Thanks! @Dhanik Lal Sahni

            – Diego Edargo Pessoa
            8 hours ago













            2














            It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.



            public class RecordTypeInfoObj {
            @AuraEnabled
            public Id recordTypeId {get;set;}
            @AuraEnabled
            public String name {get;set;}

            public RecordTypeInfoObj(Id recordTypeId, String name) {
            this.recordTypeId = recordTypeId;
            this.name = name;
            }
            }


            List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
            for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
            if(info.isAvailable()) {
            recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
            }
            }


            In lightning component define the following attribute



            <aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />





            share|improve this answer






























              2














              It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.



              public class RecordTypeInfoObj {
              @AuraEnabled
              public Id recordTypeId {get;set;}
              @AuraEnabled
              public String name {get;set;}

              public RecordTypeInfoObj(Id recordTypeId, String name) {
              this.recordTypeId = recordTypeId;
              this.name = name;
              }
              }


              List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
              for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
              if(info.isAvailable()) {
              recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
              }
              }


              In lightning component define the following attribute



              <aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />





              share|improve this answer




























                2












                2








                2







                It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.



                public class RecordTypeInfoObj {
                @AuraEnabled
                public Id recordTypeId {get;set;}
                @AuraEnabled
                public String name {get;set;}

                public RecordTypeInfoObj(Id recordTypeId, String name) {
                this.recordTypeId = recordTypeId;
                this.name = name;
                }
                }


                List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
                for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
                if(info.isAvailable()) {
                recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
                }
                }


                In lightning component define the following attribute



                <aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />





                share|improve this answer













                It is better to create separate strongly typed Apex class, if you want to use this data in lightning component.



                public class RecordTypeInfoObj {
                @AuraEnabled
                public Id recordTypeId {get;set;}
                @AuraEnabled
                public String name {get;set;}

                public RecordTypeInfoObj(Id recordTypeId, String name) {
                this.recordTypeId = recordTypeId;
                this.name = name;
                }
                }


                List<RecordTypeInfoObj> recTypeList = new List<RecordTypeInfoObj>();
                for(RecordTypeInfo info : Indicador_Clinico__c.SObjectType.getDescribe().getRecordTypeInfos()) {
                if(info.isAvailable()) {
                recTypeList.add(new RecordTypeInfoObj(info.recordTypeId, info.name));
                }
                }


                In lightning component define the following attribute



                <aura:attribute name="listOfRecordTypoInfos" type="RecordTypeInfoObj[]" />






                share|improve this answer












                share|improve this answer



                share|improve this answer










                answered 8 hours ago









                BlackCatBlackCat

                3471 silver badge11 bronze badges




                3471 silver badge11 bronze badges

























                    Diego Edargo Pessoa is a new contributor. Be nice, and check out our Code of Conduct.










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                    Diego Edargo Pessoa is a new contributor. Be nice, and check out our Code of Conduct.













                    Diego Edargo Pessoa is a new contributor. Be nice, and check out our Code of Conduct.












                    Diego Edargo Pessoa is a new contributor. Be nice, and check out our Code of Conduct.
















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