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-3

print the name of the most recently accessed file in the directory /var/run/log/ whose name is of the form access-<DDD>.log (here <DDD> represents exactly 3 digits; thus the filename consists of access- followed by exactly 3 digits, followed by .log

linux

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edited 2 days ago

Kusalananda♦

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put on hold as unclear what you're asking by Christopher, roaima, Jeff Schaller♦ 2 days ago

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What is your issue with this assignment?
  
  – Kusalananda♦
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm voting to close this question as off-topic because you're demanding we do your assignment for you without any visible attempt by yourself.
  
  – roaima
  2 days ago
  
  
  

  
  
  
  

add a comment | 

-3

print the name of the most recently accessed file in the directory /var/run/log/ whose name is of the form access-<DDD>.log (here <DDD> represents exactly 3 digits; thus the filename consists of access- followed by exactly 3 digits, followed by .log

linux

share|improve this question

edited 2 days ago

Kusalananda♦

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asked 2 days ago

ANKIT PAHARIYAANKIT PAHARIYA

2

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ANKIT PAHARIYA is a new contributor to this site. Take care in asking for clarification, commenting, and answering.
Check out our Code of Conduct.

put on hold as unclear what you're asking by Christopher, roaima, Jeff Schaller♦ 2 days ago

Please clarify your specific problem or add additional details to highlight exactly what you need. As it's currently written, it’s hard to tell exactly what you're asking. See the How to Ask page for help clarifying this question. If this question can be reworded to fit the rules in the help center, please edit the question.

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  What is your issue with this assignment?
  
  – Kusalananda♦
  2 days ago
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  I'm voting to close this question as off-topic because you're demanding we do your assignment for you without any visible attempt by yourself.
  
  – roaima
  2 days ago
  
  
  

  
  
  
  

add a comment | 

print the name of the most recently accessed file in the directory /var/run/log/ whose name is of the form access-<DDD>.log (here <DDD> represents exactly 3 digits; thus the filename consists of access- followed by exactly 3 digits, followed by .log

linux

share|improve this question

edited 2 days ago

Kusalananda♦

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asked 2 days ago

ANKIT PAHARIYAANKIT PAHARIYA

2

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Check out our Code of Conduct.

share|improve this question

edited 2 days ago

Kusalananda♦

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asked 2 days ago

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edited 2 days ago

Kusalananda♦

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edited 2 days ago

Kusalananda♦

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edited 2 days ago

Kusalananda♦

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asked 2 days ago

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2

2 Answers
2

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1

Using the zsh shell:

setopt EXTENDED_GLOB

print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])

Here, [[:digit:]](#c3) will match exactly three digit characters. After that, the string .log must occur in the name. The dot in (.oa[1]) qualifies the globbing pattern so that only regular files are matched and the oa sorts them in decreasing atime order. The [1] returns only the first matching name (the most recently accessed one). The print utility will print the resulting pathname.

Change print to basename to only output the filename, without the path.

---

If this is a homework assignment and you're supposed to write a bash script:

#!/bin/bash



zsh -o extended_glob -c 'print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])'

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

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add a comment | 

0

Try this:

ls -tu | grep -e '^access-[0-9]{3}.log$' | awk '{print $NF}'

share|improve this answer

edited yesterday

Kusalananda♦

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answered 2 days ago

pgoetzpgoetz

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• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Fixed again. I think that should do it. <:)
  
  – pgoetz
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Now awk seems unnecessary (without the -l option to ls).
  
  – fra-san
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The ^ anchor would make the expression never match with ls -l as you have more data on the line before the filename. If you really want to use ls -l, then swap places on awk and grep, or use awk '$NF ~ /^expression$/ { print $NF }' to combine them. With ls -l and print $NF in awk, you lose the ability handle filenames with spaces though. Consider doing some testing.
  
  – Kusalananda♦
  yesterday
  
  
  

  
  
  
  

add a comment | 

1

Using the zsh shell:

setopt EXTENDED_GLOB

print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])

Here, [[:digit:]](#c3) will match exactly three digit characters. After that, the string .log must occur in the name. The dot in (.oa[1]) qualifies the globbing pattern so that only regular files are matched and the oa sorts them in decreasing atime order. The [1] returns only the first matching name (the most recently accessed one). The print utility will print the resulting pathname.

Change print to basename to only output the filename, without the path.

---

If this is a homework assignment and you're supposed to write a bash script:

#!/bin/bash



zsh -o extended_glob -c 'print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])'

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

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add a comment | 

1

Using the zsh shell:

setopt EXTENDED_GLOB

print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])

Here, [[:digit:]](#c3) will match exactly three digit characters. After that, the string .log must occur in the name. The dot in (.oa[1]) qualifies the globbing pattern so that only regular files are matched and the oa sorts them in decreasing atime order. The [1] returns only the first matching name (the most recently accessed one). The print utility will print the resulting pathname.

Change print to basename to only output the filename, without the path.

---

If this is a homework assignment and you're supposed to write a bash script:

#!/bin/bash



zsh -o extended_glob -c 'print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])'

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

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add a comment | 

Using the zsh shell:

setopt EXTENDED_GLOB

print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])

Here, [[:digit:]](#c3) will match exactly three digit characters. After that, the string .log must occur in the name. The dot in (.oa[1]) qualifies the globbing pattern so that only regular files are matched and the oa sorts them in decreasing atime order. The [1] returns only the first matching name (the most recently accessed one). The print utility will print the resulting pathname.

Change print to basename to only output the filename, without the path.

---

If this is a homework assignment and you're supposed to write a bash script:

#!/bin/bash



zsh -o extended_glob -c 'print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])'

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

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setopt EXTENDED_GLOB

print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])

#!/bin/bash



zsh -o extended_glob -c 'print /var/run/log/access-[[:digit:]](#c3).log(.oa[1])'

share|improve this answer

edited 2 days ago

answered 2 days ago

Kusalananda♦Kusalananda

160k1818 gold badges317317 silver badges504504 bronze badges

answered 2 days ago

Kusalananda♦Kusalananda

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answered 2 days ago

Kusalananda♦Kusalananda

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0

Try this:

ls -tu | grep -e '^access-[0-9]{3}.log$' | awk '{print $NF}'

share|improve this answer

edited yesterday

Kusalananda♦

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answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Fixed again. I think that should do it. <:)
  
  – pgoetz
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Now awk seems unnecessary (without the -l option to ls).
  
  – fra-san
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The ^ anchor would make the expression never match with ls -l as you have more data on the line before the filename. If you really want to use ls -l, then swap places on awk and grep, or use awk '$NF ~ /^expression$/ { print $NF }' to combine them. With ls -l and print $NF in awk, you lose the ability handle filenames with spaces though. Consider doing some testing.
  
  – Kusalananda♦
  yesterday
  
  
  

  
  
  
  

add a comment | 

0

Try this:

ls -tu | grep -e '^access-[0-9]{3}.log$' | awk '{print $NF}'

share|improve this answer

edited yesterday

Kusalananda♦

160k1818 gold badges317317 silver badges504504 bronze badges

answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges

• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  Fixed again. I think that should do it. <:)
  
  – pgoetz
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  @Kusalananda Now awk seems unnecessary (without the -l option to ls).
  
  – fra-san
  yesterday
  

  
  
  
  


• 
  
  
  

  
  

  
  
  
  
  
  

  
  
  The ^ anchor would make the expression never match with ls -l as you have more data on the line before the filename. If you really want to use ls -l, then swap places on awk and grep, or use awk '$NF ~ /^expression$/ { print $NF }' to combine them. With ls -l and print $NF in awk, you lose the ability handle filenames with spaces though. Consider doing some testing.
  
  – Kusalananda♦
  yesterday
  
  
  

  
  
  
  

add a comment | 

Try this:

ls -tu | grep -e '^access-[0-9]{3}.log$' | awk '{print $NF}'

share|improve this answer

edited yesterday

Kusalananda♦

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answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges

ls -tu | grep -e '^access-[0-9]{3}.log$' | awk '{print $NF}'

share|improve this answer

edited yesterday

Kusalananda♦

160k1818 gold badges317317 silver badges504504 bronze badges

answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges

edited yesterday

Kusalananda♦

160k1818 gold badges317317 silver badges504504 bronze badges

edited yesterday

Kusalananda♦

160k1818 gold badges317317 silver badges504504 bronze badges

answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges

answered 2 days ago

pgoetzpgoetz

45455 silver badges1111 bronze badges